Question

Calculate the volume of oxygen at NTP that would be required to convert 5.2 L of carbon monoxide to carbon dioxide.

• A. 5.2 L
• B. 2.5L
• C. 3.52 L
• D. None of these

Answer 1

The correct option is B 2.5L

According to ideal gas law, the volume occupied by $1$ mole of a gas at $NTP$ or $STP$ is $22.4$ liters.

Final moles of $5$ liters of $CO$ :

It $22.4$ liters of $CO$ is $1$ mole

then $5$ liters of $CO=1\times \frac{5}{22.4}=0.223$ moles

The equation for the reaction of the oxidation of $CO$ is

The mole ratio between $CO$ and $O_2$ in the equation is $2:1$

The mole of $5L$ $CO$ is $0.223$ moles

mole ratio is $2:1$. That means we need $=\frac{0.223}{2}=0.112$

$0.112$ moles of oxygen to react with $CO$

Then $0.112$ moles $=0.112\times 22.4/1=2.5$ litres