Calculate the volumetric composition of water.

2:1 by volume

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3:1 by volume

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1:2 by volume

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1:1 by volume

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Solution

The correct option is A
2:1 by volume

$2 H_{2} O$ $\to$ $2 H_{2}$ + $O_{2}$

2 vol. 2 vol. 1 vol.

Total = 3 vol.

Hence, the volumetric composition of water is

$H_{2} = \frac{2}{3} \times 100$ = 66.66%

$O_{2} = \frac{1}{3} \times 100$ = 33.33%

or $H_{2} : O_{2} i n H_{2} O$ = 66.66 : 33.33 = 2:1 by volume.

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Calculate the volumetric composition of water.

The correct option is A 2:1 by volume 2H2O → 2H2 + O2 2 vol. 2 vol. 1 vol. Total = 3 vol. Hence, the volumetric composition of water is H2=23×100 = 66.66% O2=13×100 = 33.33% or H2:O2 in H2O = 66.66 : 33.33 = 2:1 by volume.