Question

Calculate the water pressure and the thrust at the bottom of a tank whose length, width and the depth are $2m,1.5mand1m$ respectively. Density of water is $1000kg{m}^{-3}$.

Answer 1

Pressure $\left(P\right)$ at the bottom of the tank is given by $P=hdg$
$=1m\times 1000kg\times 9.8m{s}^{-2}=9800N{m}^{-2}$
Surface area at the bottom of the tank $=2m\times 1.5m=3m^2$
$\therefore Thrustatthebottomofthetank=force\times area$
$=9800N{m}^{-2}\times 3m^2=29,400N$.