Question

Calculate the wavelength of the electron if it moving with a velocity of $2.05\times {10}^{7}m{s}^{-1}$.

Answer 1

Step 1: Given data

Velocity of the electron = $2.05\times {10}^7$ m/s

m = mass of particle($9.1\times {10}^{-31}kg$ )

v = velocity of particle($2.05\times {10}^7\frac{m}{s}$)

h = Planck's constant($6.626\times {10}^{-34}Js$)

Step 2: Formula used

$\lambda =h/mv\; (de\; Broglie\text{'}s\; equation)$

Where, $\lambda =$ wavelength of moving particle

Step 3: Finding the wavelength

λ = $\frac{6.626\times {10}^{-34}}{9.1\times {10}^{-34}\times 2.05\times {10}^7}$ = $3.55\times {10}^{-11}m$

Hence, the wavelength of the electron is $3.55\times {10}^{-11}m$ .

m=m

$\lambda$λ=(6626×10−34 Js)(9.109×10−31)(2.05×107 ms−1)\lambda=\cfrac{(6626\times 10^{-34}\ Js)}{(9.109\times 10^{-31})(2.05\times 10^{7}\ ms^{-1})}