Calculate the weight of CO having same no. of oxygen atoms present in 88gms of CO2.

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Solution

Molar Mass of CO2=44g

No of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant

no of oxygen atoms = weight of CO/28 × Avogadro's constant

no of oxygen atoms in CO2 = no of oxygen atoms in CO

2× 88/44 = weight of CO/28

weight of CO = 112 g

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