Question

Calculate the weight of gold having specific heat capacity 0.13 J (C) g which is heated from 25 to 300 degree centigrade, where the heat absorbed is 1500J.

Answer 1

Given :
q = 1500 J
m = ?
Cp = 0.13J/gC
dT = 300-25 = 275 C
q = m x Cp x dT
rearrange the equation
m = q/Cp x dT
m = 1500 J / (0.13 J/gC x 275 C)
m =41.958 g
m = 41.96g ( is the weight of gold)