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Work done in Isothermal Irreversible Process

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Question

Calculate the work done when $5$ moles of oxygen gas contracts isothermally from $85 L$ to $15 L$ against a constant pressure of $2 a t m$ at $25^{0} C$ .

70 L a t m

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14.0 L a t m

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140 L a t m

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7.0 L a t m

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Solution

The correct option is C $140 L a t m$
We know, work done for an isothermal irreversible process is given as:
$w = - P_{e x t} (V_{2} - V_{1})$
where $P_{e x t}$ = external pressure = $1 a t m$
$V_{2}$ = final volume = $15 L$
$V_{1}$ = initial volume = $85 L$
so, $(V_{2} - V_{1}) = - 70 L$
$w = - 2 \times - 70 = 140 L a t m$

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