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Question

Calculate the vapor pressure of an aqueous solution of 1 molal glucose solution at 100 degrees Celsius.


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Solution

Step 1: Given data

Molality=1m;

Temperature=100oC

Step:2 Introducing the Formula:

Po-PPo=W2M2×M1W1

Step: 3 Calculating the mass of solvent using the given molality:

molality=W2M2×W1×10001m=W2M2×W1×100011000=W2M2×W1W2M2×W1=0.001

Step:4 Putting all the values in the above-mentioned equation:

760-P760=W2M2×1W1×M1760-P760=0.001×18=0.018760-P=0.018×760=13.68P=760-13.78=746.32unit

Therefore, the vapor pressure of an aqueous solution of 1 molal glucose solution at 100 degrees Celsius is 746.32units.


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