Calculate volume of carbon dioxide produced on heating $10 g$ of limestone at S.T.P?

3.24 L

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22.4 L

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2.24 L

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0.224 L

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Solution

The correct option is C 2.24 L
$C a C O_{3} ⟶ C a O + C O_{2}$
1 mole of limestone gives 1 mole of carbon dioxide, i.e.
Amount of $C O_{2}$ given by 100 g of $C a C O_{3} = 22.4 L$
Amount of $C O_{2}$ given by 10 g of $C a C O_{3} = \frac{22.4}{100} \times 10 = 2.24 L$
Hence, the correct answer is 2.24 L.

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