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Abundance and Isotopes

Calulate the ...

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Calulate the no of moles in 6.023×10^{23}atoms of O in CO_{

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C O_{2}

Q. Find the total number of moles of electrons in

6.023 \times 10^{23} N O_{3}^{-}

Q. The number of sodium atoms in

2

moles of sodium ferrocyanide

N a_{4} [F e (C N)_{6}]

Q. From 320 mg. of

O_{2}

6.023 \times 10^{20}

molecules are removed, the no. of moles remained are

320 m g

O_{2}, 6.023 \times 10^{20}

molecules are removed, the no. of moles remained are:

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