Question

Can $172$ pears be evenly distributed among $4$ vendors? If yes, how many pears would one vendor get?

• A. Yes.
• B. No.
• C. One vendor woud get $43$ pears.
• D. One vendor woud get $18$ pears.

Answer 1

Answer: (A), (C)

One vendor woud get $43$ pears.

For $172,$ last two digits are $57.$

$72$ is divisible by $4.$
$\therefore 172$ pears can be evenly distributed among $4$ vendors.

$\text{Nomber of pears each vendor would get}=\frac{\text{Total number of pears}}{\text{Total number of vendors}}=\frac{172}{4}\text{pears}=\frac{100+72}{4}\text{pears}=\frac{100}{4}+\frac{72}{4}\text{pears}=25+\frac{18\times 4}{4}\text{pears}=25+18\text{pears}=43\text{pears}$