Capillary tubes of diameter $1, 1.5, 2 m m$ are dipped vertically in the same liquid. The capillary ascents of the liquid in the tube are in the ratio

2 : 3 : 4

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6 : 4 : 3

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3 : 4 : 6

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4 : 3 : 2

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Solution

The correct option is B $6 : 4 : 3$
we know that $h \propto \frac{1}{d}$
where h is capillary ascents of the liquid in the tube. and d is diameter.

so It is given that $d_{1} : d_{2} : d_{3} :: 1 : 1..5 : 2$

so $h_{1} : h_{2} : h_{3} :: 1 : \frac{2}{3} : \frac{1}{2}$

$h_{1} : h_{2} : h_{3} :: 6 : 4 : 3$

Hence option B is correct.

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Capillary tubes of diameter 1,1.5,2 mm are dipped vertically in the same liquid. The capillary ascents of the liquid in the tube are in the ratio

The correct option is B 6:4:3we know that h∝1dwhere h is capillary ascents of the liquid in the tube. and d is diameter.so It is given that d1:d2:d3::1:1..5:2so h1:h2:h3::1:23:12h1:h2:h3::6:4:3Hence option B is correct.

Capillary tubes of diameter $1, 1.5, 2 m m$ are dipped vertically in the same liquid. The capillary ascents of the liquid in the tube are in the ratio