Question

Car X and car Y traveled the same 80 kms route. If car X took 2 hours and car Y traveled at an average speed that was 50 percent faster than the average speed of car X, how many hours did it take car Y to travel the route?

• A.
• B.
• C. 1
• D.

Answer 1

The correct option is B

$\text{Average speed of car}X=\frac{80}{2}=40kmph:\text{Average speed of car}Y=(\frac{50}{100}\times 40)+40=60\text{No. of hours taken by Car}Y=\frac{80}{60}=1\frac{1}{3}$