1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Carbon monoxide is allowed to expand isothermally and reversibly from 15 m3 to 30 m3 at 300 K and work obtained is 8.595 kJ. Calculate the number of moles of carbon monoxide. Take R = 8.3 J K−1mol−1 and ln2 = 0.69

A
5.00 mol
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4.72 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.33 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7.82 mol
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 5.00 molWork done in an isothermal reversible process is given as: w=−nRT lnV2V1 Given: V1=15 m3 V2=30 m3 T=300 K R=8.3 J K−1mol−1 W=−8.585×103 J (as work is done by the system) So, −8.595×103=− n×8.3 ×300 × ln2010 On solving we get, n=5 mol

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
First Law of Thermodynamics
CHEMISTRY
Watch in App
Join BYJU'S Learning Program