Question

Cards are drawn from a pack of 52 cards one by one. The probability that exactly 10 cards will be drawn before the first ace is:

• A. $\frac{241}{1456}$
• B. $\frac{164}{4165}$
• C. $\frac{51}{884}$
• D. $Noneofthese$

Answer 1

The correct option is B $\frac{164}{4165}$

P {(first 10 draws non - ace) (${11}^{th}$ ace)}
$\frac{{}^{48}{C}_{10}}{{}^{52}{C}_{10}}\times \frac{4}{42}=\frac{164}{4165}$