Cation having maximum number of unpaired electrons is:

M n^{2 +}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F e^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C o^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N i^{2 +}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $M n^{2 +}$
$M n^{+ 2}$ is a cation of manganese which contain 5 unpaired electron in $3 d$ subshell.

Suggest Corrections

Similar questions

N i^{2 +}

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

M n^{2 +}, C o^{2 +}, Z n^{2 +} & N i^{2 +}

C u^{2 +}, N i^{2 +}, C o^{2 +}, F e^{2 +}

M n^{2 +}

F e^{2 +}

Join BYJU'S Learning Program