CCH3COOH(l)+C2H5OH(l) = CH3COOH(l)+ H2O(l) What is the equilibrium constant??

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Q. In the esterfication

C_{2} H_{5} O H (l) + C H_{3} C O O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)

an equimolar mixture of alcohol and acid taken initially yields under equilibrium, the water with mole fraction = 0.333. Calculate the equilibrium constant.

Q. In the esterification

C_{2} H_{5} O H (l) + C H_{3} C O O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)

an equimolar mixture of alcohol and acid taken initially yields under equilibrium, the water with mole fraction

= 0.333.

Calculate the equilibrium constant :

$C H_{3} C O O H (l) + C_{2} H_{5} O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)$

In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of

little conc. $H_{2} S O_{4}$ . On equilibrium being attained

Q. If different quantities of ethanol and acetic acid are used in the following reversible reaction,

{C H}_{3} C O O H (l) + C_{2} H_{5} O H (l) ⇌ {C H}_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)

, the equilibrium constant will have values which will be:

$C H_{3} C O O H (l) + C_{2} H_{5} O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l); K_{c} = 4$

In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. $H_{2} S O_{4}$ . On equilibrium being attained

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