Question

$Ce-58$ is a member of

• A. $s-block$ elements
• B. $p-block$ elements
• C. $d-block$ elements
• D. $f-block$ elements

Answer 1

Answer: (D)

$f-block$ elements

The electronic configuration of $Ce$ is ${}_{58}Ce=[Xe{]}_{54}4f^{2}6s^{2}5d^0$. Because of the presence of partially filled f-orbitals, $Ce$ is a f-block element.