Question

$\frac{{2.3}^{n+1}+{7.3}^{n-1}}{3^{n+2}-2{\left(\frac{1}{3}\right)}^{1-n}}$ is equal to

• A. 1
• B. 3
• C. -1
• D. 0

Answer 1

Answer: (A)

1

We have,

$\frac{{2.3}^{n+1}+{7.3}^{n-1}}{3^{n+2}-2{\left(\frac{1}{3}\right)}^{1-n}}$

$\Rightarrow \frac{{6.3}^n+\frac{7}{3}{.3}^n}{{9.3}^n-\frac{2}{3}.3^n}$

$\Rightarrow \frac{{18.3}^n+{7.3}^n}{{27.3}^n-2.3^n}$

$\Rightarrow \frac{{25.3}^n}{{25.3}^n}$

$\Rightarrow 1$

Hence, this is the answer.