Question

$C{H}_2=C{H}_2\stackrel{B{r}_2/H_{2}O}{\to }A,$

In the above reaction the compound 'A' is

• A. Ethylene bromohydrin
• B. 1, 2-dibromo ethane
• C. Ethanol
• D. None of these

Answer 1

The correct option is A Ethylene bromohydrin

a) $C{H}_2=C{H}_2\stackrel{B{r}_2,H_{2}O}{\to }\underset{Ethylene}{\underset{Br}{\underset{|}{C{H}_2}}}-\underset{bromohydrin}{\underset{OH}{\underset{|}{C{H}_2}}}$

Hence compound A is Ethylene bromohydrin.