$C H_{2} = C H - C H_{2}, C F_{3} C H_{2}$ What is the sequence of stability?

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Solution

Carbon is a molecule contain a neutral carbonation with a valance of two unleashed valance electron.
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Acc to que- $C H_{2} = C H - C H_{2} > C F_{3} C H_{2}$
Carbon has $2$ non-bonded electron. The carbon should be either $s p^{2}$ or sp hybridised .
In either case these are two non-bonding orbitals which are an $s p^{2}$ and a $p$ orbital in formal case. Ace to hund rule multiplicity rule the two $e^{-}$ should occupy the two available orbital having $2$ opposite parallel spins.
Triplet carbon > singlet carbon

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C H_{2} = C H - C H = C H - + C H_{2}

C H_{2} = C H - + C H - C H = C H_{2}

C H_{2} = C H - + C H - - C H - + C H_{2}

+ C H_{2} - C H = C H - - C H - + C H_{2}

(A) C H_{3} - C H_{2} - C | C O O H H - - C H - C H_{3}

(B) C H_{3} - C | C O O H H - C H_{2} - - C H - C H_{3}

(C) C | C O O H H_{2} - C H_{2} - C H_{2} - - C H - C H_{3}

C H_{3} - C H_{2} - \oplus C H_{2}

C H_{3} - C H | F - \oplus C H_{2}

C H_{3} - C H | B r - \oplus C H_{2}

C H_{3} - C H | C l - \oplus C H_{2}

+ C H_2 - C H = C H_{2}

C H_{2} = C H (I) - \oplus C H_{2}; C H_{3} - C H_{2} (I I) - \oplus C H_{2};

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