Question

$(C{H}_3{)}_{3}CCl\stackrel{NaCN}{\to }A\stackrel{dil.H_{2}S{O}_4}{\to }B$. Compund B is

• A. $(C{H}_3{)}_{3}CCOOH$
• B. $(C{H}_3{)}_{3}COH$
• C. $\left(C{H}_3{)}_{3}COC\right(C{H}_3{)}_3$
• D. All the three

Answer 1

The correct option is B

$(C{H}_3{)}_{3}COH$

$C{N}^{-}$ is a strong base since the substrate is a tert-halide, it mainly undergoes elimination reaction forming alkene (A). In presence of dil. $H_{2}S{O}_4$, alkenes undergo hydration in Markovnikov's way.