CH3 - C - CH - H2O H2SO4AThe product A in above reaction is-

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CH3 - C ≡ CH ...

Question

$C H_{3} - C \equiv C H + H_{2} O H g S O_{4} - --- \to H_{2} S O_{4} (A)$
The product $A$ in above reaction is:

propanal

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propanone

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propene

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both (a) and (b)

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C H_{3} - C H = C H_{2} (1) T H F : B D_{3} - ------- \to (2) C H_{3} C O_{2} T (A)

H_{2} 14 C = C H - C H_{3} l o w c o n c . o f B r_{2} - --------- \to o r h i g h t e m p (?)

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C H_{3} C H_{2} - C H_{3} | C | C H_{3} - C | H O H - C H_{3} H_{2} S O_{4} - --- \to h e a t P M a j o r

C H_{3} - C H_{3} | C = C H - C H_{3} H g (O A c)_{2} / E t O H - --------- \to (A) (90)

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