Question

$C{H}_3-\stackrel{C{H}_3}{\stackrel{|}{C}}=CH-C{H}_3\stackrel{Hg(OAc{)}_2/EtOH}{\to }\underset{\left(90\right)}{\left(A\right)}$
Product (A) of the reaction is:

• A. $C{H}_3-\underset{HgOAc}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{OEt}{\underset{|}{CH}}-C{H}_3$
• B. $C{H}_3-\underset{OEt}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{HgOAc}{\underset{|}{CH}}-C{H}_3$
• C. $C{H}_3-\underset{OH}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{HgOAc}{\underset{|}{CH}}-C{H}_3$
• D. $C{H}_3-\underset{HgOAc}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{OH}{\underset{|}{CH}}-C{H}_3$

Answer 1

The correct option is B $C{H}_3-\underset{OEt}{\underset{|}{\stackrel{C{H}_3}{\stackrel{|}{C}}}}-\underset{HgOAc}{\underset{|}{CH}}-C{H}_3$

Oxymercuration process is a two step process inwhich product formation occurs through markanikov addition.