The correct option is D trans-3-hexene
The product P is trans-3-hexene. When 3-hexyne is reduced with Na in liq ammonia, trans-3-hexene is obtained. In this reaction, carbon carbon tripple bond is selectively reduced to C=C double bond. The alkene formed is trans alkene as the addition of molecule of hydrogen to carbon carbon tripple bond is trans.
CH3−CH2−C≡C−CH2−CH3Nain−−−−→LiqNH3cis−CH3−CH2−C=C−CH2−CH3