You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reimer Tiemann Reaction

CH3-CH2-CH2-O...

Question

$C H_{3} - C H_{2} - C H_{2} - O - C | | S - S - C H_{3}$ undergoes elimination on strong heating giving $C H_{3} - C H = C H_{2}, C H_{3} S H$ and $C O S$ . This reaction involves :

formation of cyclic intermediate

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

syn elimination

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

anti elimination

No worries! We‘ve got your back. Try BYJU‘S free classes today!

first order kinetics

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A formation of cyclic intermediate
B syn elimination
D first order kinetics
Pyrolysis of xanthate esters is known as Chugaev reaction. The reaction involves cyclic intermediate. It follows syn elimination. The reaction follows first order kinetics.

Suggest Corrections

Similar questions

A g N O_{3}

i) C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - O = C H_{2} - C H_{3}

i i) C H_{3} - C H_{2} - C H_{2} - O - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

Join BYJU'S Learning Program