$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by:

catalytic hydrogenation

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treatement with

L i A l H_{4}

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treatment with pyridinium chlorochromate

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treatement with

K M n O_{4}

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Solution

The correct option is C treatment with pyridinium chlorochromate
$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by treatement with pyridinium chlorochromate. Primary alcohols on oxidation gives aldehydes. Further oxidation of aldehydes in the presesnce of strong oxidizing agent gives carboxylic acids.
To stop oxidation at aldehyde stage and to prevent further oxidation to carboxylic acid, a mild oxidizing agent such as pyridinium chlorochromate is used.

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Similar questions

C H_{3} C H_{2} O H

is converted into

C H_{3} C H O

in the presence of:

{C H}_{3} {C H}_{2} O H

can be converted into

{C H}_{3} C H O

by:

$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by . . . .
(a) catalytic hydrogenation
(b) treatment with $L i A I H_{4}$
(c) treatment with pyridinium chlorochromate
(d) treatment with $K M n O_{4}$

Q. Assertion (A):

C H_{3} C H_{2} O H

can be converted into

C H_{3} C H O

by treatment with pyridinium chlorochromate.

Reason (R): PCC is a better reagent for oxidation of primary alcohols to aldehydes.
[1 Mark]

X,Y and Z are three organic compounds. All the three undergo iodoform test .Only Y and Z can react with 2,4 -DNP. Only Z can reduce tollen's reagent. Here X,Y and Z respectively

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CH3CH2OH can be converted into CH3CHO by:

$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by: