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Hydrohalogenation of Alkenes

CH3 CH = CH2 ...

Question

$C H_{3} C H = C H_{2} + H B r$ gives :

C H_{2} = C H - C H_{2} - B r

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C H_{3} - C H_{2} - C H_{2} - B r

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C H_{3} C H (B r) - C H_{3}

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C H_{3} - C H_{2} - C H_{3}

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Solution

The correct option is C $C H_{3} C H (B r) - C H_{3}$
This is an example of addition reaction.

The double bond is broken and hydrogen and bromine are added to the given compound.

Bromine will add up on secondary carbon. (Markovnikov's Rule)

$C H_{3} C H = C H_{2} + H B r \to C H_{3} C H (B r) - C H_{3}$

Option C is correct.

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Similar questions

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

{C H}_{2} = C H - {C H}_{3} + H B r \to {C H}_{3} C H (B r) - {C H}_{3}

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