Question

${CH}_{3}COOH\stackrel{LiAl{H}_4}{\to }A+{CH}_{3}COOH\underset{}{\overset{H_3{O}^{+}}{\to }}B+H_{2}O$
In the above reactions $A$ and $B$ respectively are

• A. ${CH}_{3}COO{C}_2{H}_5,C_2{H}_{5}OH$
• B. ${CH}_{3}CHO,C_2{H}_{5}OH$
• C. $C_2{H}_{5}OH,{CH}_{3}CHO$
• D. $C_2{H}_{5}OH,{CH}_{3}COO{C}_2{H}_5$

Answer 1

The correct option is D $C_2{H}_{5}OH,{CH}_{3}COO{C}_2{H}_5$

${CH}_{3}COOH+4H\underset{}{\overset{LiAl{H}_4}{\to }}\underset{\left(A\right)}{{CH}_3{CH}_{2}OH}+H_{2}O$
$\underset{\left(A\right)}{{CH}_3{CH}_{2}OH}+{CH}_{3}COOH\underset{}{\overset{H_3{O}^{+}}{\to }}\underset{\left(B\right)}{{CH}_{3}COO{C}_2{H}_5}+H_{2}O$

Option D is correct.