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Question
CH3−CH3|C|CH3BrKOH(alcoholic)−−−−−−−−−−→Δ(A)HBr/R2O2−−−−−−−−→(B)(major
What is product B?
CH3−CH3|C|CH3BrKOH(alcoholic)−−−−−−−−−−→Δ(A)HBr/R2O2−−−−−−−−→(B)(major
What is product B?
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Solution
The correct option is A CH3−CH3|C|H−CH2−Br
(A)CH3−CH3|C|CH3−Bralc.KOH−−−−−→ΔCH3−CH3|C=CH2+HBr(B)Ch3−CH3|C=CH2HBr/H2O2−−−−−−−→CH3−CH3|CH−CH2−Br
Here tert-butylbromidw undergoes β 0elimination reaction to form isobutylene (A).
Product A when reacts with HBr/H2O2 it follows Anti-Markownikoff's rule to give 1-Bromo-2-methyl Propane as a product.
Hence the correct option is A
(A)CH3−CH3|C|CH3−Bralc.KOH−−−−−→ΔCH3−CH3|C=CH2+HBr
(B)Ch3−CH3|C=CH2HBr/H2O2−−−−−−−→CH3−CH3|CH−CH2−Br
Here tert-butylbromidw undergoes β 0elimination reaction to form isobutylene (A).
Product A when reacts with HBr/H2O2 it follows Anti-Markownikoff's rule to give 1-Bromo-2-methyl Propane as a product.
Hence the correct option is A
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