Question

$C{H}_3-\stackrel{\stackrel{C{H}_3}{|}}{\underset{\underset{C{H}_3}{|}}{C}}-X\stackrel{alc.KOH}{\to }$
'X' is halogen
Choose the correct statement for the above reaction is :

• A. $\beta$ elimination reaction
• B. product will be 2-methylpropene
• C. Dehydrohalogenation reaction
• D. All of the above.

Answer 1

The correct option is D All of the above.

Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting $\beta -H$ from a substrate in presence of base (alc. KOH) to form alkenes.
Since, removal of $\beta$ hydrogen takes place in elimination step thus it's a $\beta$ elimination reaction.
$C{H}_3-\stackrel{\stackrel{C{H}_3}{|}}{\underset{\underset{C{H}_3}{|}}{C}}-X\stackrel{alc.KOH}{\to }C{H}_3-\underset{\underset{C{H}_3}{|}}{C}=C{H}_2+H_{2}O+KX$