CH3- CH3- CH-CH-CH2-HBr product which is Prodominate - X is

The correct option is B CH_3 Br| CH_3|C CH_2 CH_3 CH_3 CH_3|CH CH=CH_2+HBr→ CH_3 CH_3|CH C^⊕ CH_3 #160; #160; #160; #160; #160; ...

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Introduction

CH3- CH3| C...

Question

$C H_{3} - C H | C H_{3} - C H = C H_{2} + H B r$ product which is Prodominate : $X$ is

C H_{3} C H | C H_{3} - C H_{2} C H_{2} B r

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C H_{3} - B r | C | C H_{3} - C H_{2} - C H_{3}

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C H_{3} - C H | C H_{3} - C H | B r - C H_{3}

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S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

(A) C H_{3} - C H_{2} - C | B r H - + C H - C H_{3}

(B) C H_{3} - C H_{2} - C | I H - + C H - C H_{3}

C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

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