Question

$C{H}_3-\underset{Et}{\underset{|}{CH}}-OAc\stackrel{H{O}^{-}}{\to }$
(d)-(d=dextro rotatory)

Product of the reaction is :

• A. $C{H}_3-\underset{\left(d\right)}{\stackrel{Et}{\stackrel{|}{CH}}}-OH$
• B. $C{H}_3-\underset{\left(l\right)}{\underset{Et}{\underset{|}{CH}}}-OH$
• C. $C{H}_3-\underset{\left(d\right)and\left(l\right)}{\underset{Et}{\underset{|}{CH}}}-OH$
• D. $C{H}_3-\underset{C{H}_3}{\underset{|}{CH}}=C{H}_2$

Answer 1

The correct option is A $C{H}_3-\underset{\left(d\right)}{\stackrel{Et}{\stackrel{|}{CH}}}-OH$

Ester base Hydrolysis mechanism is as follows:-