$C H_{3} C H_{2} - C l$ undergoes homolytic fission to produce:

C H_{3} ˙ C H_{2}

and

˙ C l

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C H_{3} ˙ C H_{2}

and

C l^{\oplus}

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C H_{3} C^{\oplus} H_{2}

and

C l^{-}

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C H_{3} C^{\oplus} H_{2}

and

˙ C l

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Solution

The correct option is A $C H_{3} C^{\oplus} H_{2}$ and $C l^{-}$
Homolytic cleavage is the breaking of a covalent bond in such a way that each fragment gets one of the shared electrons.

The word homolytic comes from the Greek homoios, "equal", and lysis, "loosening".

For example, the homolytic cleavage of a $C — C l$ bond is

Homolytic cleavage produces free radicals — atoms with unpaired valence electrons.
$H_{3} C H_{2} C^{-} C l ⟶ H_{3} C H_{2} C^{\oplus}$ and $C l^{-}$

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Similar questions

{C H}_{3} {C H}_{2} - C l

undergoes homolytic fission to produce :

Given the standard reduction potentials:

Zn²⁺/Zn = - 0.74 V, Cl₂/Cl^- = 1.36 V, H⁺/1/2H₂ = 0 V and Fe³⁺/Fe²⁺ = 0.77 V.
The order of increasing strength as reducing agent is

Q. Heat evolved in the reaction

H_{2} + C l_{2} \to 2 H C l

182

KJ. Bond energies of

H - H

and

C l - C l

are

430

and

242

KJ/mol respectively.

Thus

H - C l

bond energy is :

Q. Heat evolved in the reaction

H_{2} + {C l}_{2} ⟶ 2 H C l

is 182 kJ. Bond energies pf H-H and Cl-Cl are 430 and 242 KJ/mol respectively. The H-Cl bond energy is:

Q. In which of the following reaction +E effect is operative?

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CH3CH2−Cl undergoes homolytic fission to produce:

$C H_{3} C H_{2} - C l$ undergoes homolytic fission to produce: