wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

CH3CH2COOH Cl2 ,alcoholicKOH−−−−−−−−−−−−→redP
End product of the above given reaction is:

A
CH3CH(OH)COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
CH2(OH)CH2COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
CH2=CHCOOH
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
CH2(Cl)CH(OH)COOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C CH2=CHCOOH
Here first propionic acid undergoes chlorination to form 2-chloro propionic acid which on further reaction with alc. KOH undergoes β-elimination reaction to form prop-2-enoic acid.

Hence, option C is correct.

124071_78550_ans.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alkanes - Preparation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon