$C H_{3} C H O d i l \cdot N a O H ⟶ A Δ, d e h y d r a t i o n ⟶ B N i / H_{2} ⟶ C N i / H_{2} ⟶ D$
In the above sequence of reactions, compound D is:

C H_{3} C H_{2} C H_{2} C H_{2} O H

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C H_{3} C H_{2} C H_{2} C H O

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C H_{3} C H_{2} C H_{2} O H | C H - C H_{3}

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C H_{3} C H_{3} | C H C H O

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Solution

The correct option is A $C H_{3} C H_{2} C H_{2} C H_{2} O H$
$C H_{3} C H O D i l N a O H - ---------- \to a l d o l c o n d e n s a t i o n C H_{3} C H (O H) C H_{2} C H O 3 - h y d r o x y b u t a n a l (A) Δ d e h y d r a t i o n \to C H_{3} C H = C H C H O c r o t o n a l d e h y d e (B) N i / N H_{2} - ----- \to h y d r a t i o n C H_{3} C H_{2} C H_{2} C H O 1 - b u t a n a l (C)$
$N i / H_{2} \to C H_{3} C H_{2} C H_{2} C H_{2} O H b u t a n a - 1 - o l (D)$

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Similar questions

2 C H_{3} C H O O H^{⊖} - -- \to A △ - \to B;

{C H}_{3} - C H = C H - C H = C H - {C H}_{3} O_{3} / H_{2} / Z n - ------- \to X + Y

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

H_{2} = C H - C | C H_{3} H - C | C_{2} H_{5} H - C | O H H - C H_{3}

C H_{3} C O O^{-} N a^{+} + 2 H_{2} O \to C H_{3} C H_{3} + 2 C O_{2} + H_{2} + 2 N a O H

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