$C H_{3} C O O C_{2} H_{5} a n d C_{2} H_{5} C O O C H_{3}$ exhibit?

Metamerism

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Functional isomerism

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Position isomerism

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Tautomers

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Solution

The correct option is A Metamerism
$C H_{3} C O O C_{2} H_{5} a n d C_{2} H_{5} C O O C H_{3}$ , the alkyl groups on either side are different. Hence, they are metamers.

The difference is that in the first one a methyl group is attached to the carbon whereas in the second an ethyl group is attached to the carbon.

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Similar questions

C H_{3} C O O C_{2} H_{5} a n d C_{2} H_{5} C O O C H_{3}

C H_{3} C O O C_{2} H_{5} a n d C_{2} H_{5} C O O C H_{3}

C H_{3} C O O H L i A L H_{3} - ---- \to (A)

(A) + C H_{3} C O O H H_{3} O^{+} - -- \to (B) + H_{2} O

C H_{3} C O O C_{2} H_{5}

C_{2} H_{5} M g B r

C H_{3} C O O C_{2} H_{5}

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