$C H_{3} C O O C_{2} H_{5}$ with excess of $C_{2} H_{5} M g B r$ and hydrolysis gives:

C H_{3} - C | C_{2} H_{5} = O

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C H_{3} - C_{2} H_{5} | C | C_{2} H_{5} - O H

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C H_{3} - C | C H_{3} = O

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C H_{3} - C_{2} H_{5} | C | C H_{3} - O H

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Solution

The correct option is B $C H_{3} - C_{2} H_{5} | C | C_{2} H_{5} - O H$
Esters on reaction with excess of Grignard reagent produce $3^{o}$ alcohol.

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I U P A C

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