Question

$C{H}_3{O}^{\ominus }+C_2{H}_{5}OH\stackrel{K_{eq}}{\rightleftharpoons }C{H}_{3}OH+C_2{H}_5{O}^{\ominus }$
The equilibrium constant, $K_{eq}$ for this reaction would be:

• A. $K_{eq}>1$
• B. $K_{eq}=1$
• C. $K_{eq}<1$
• D. none of these

Answer 1

The correct option is C $K_{eq}<1$

$\text{Given,}{CH}_3{O}^{\Theta }+C_2{H}_{5}OH\Rightarrow {CH}_{3}OH+C_2{H}_5{O}^{\odot }$

$\left(A\right)$ $\left(B\right)$

Here, too conjugate bases $A$ and $B$ are formed.

But, $A$ is more stable than B. (carbanion stability)

Thus, this equilibrium farours in backward direction,

due to shich $\overline{keq}<1$

so, correct option is (c)