$C H \equiv C H, C H_{3} - C \equiv C H, N H_{3}, C H_{3} - N H_{2}$
Find the order of acidic nature using $I$ effect.

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Solution

Given compounds are
$C H \equiv C H, {C H}_{3} - C \equiv C H, {N H}_{3}, {C H}_{3} - {N H}_{2}$ .
The order of acidic nature is.
${C H}_{3} - C \equiv C H > C H \equiv C H > {N H}_{3} > {C H}_{3} - {N H}_{2}$ .

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Similar questions

{C H}_{3} - C H = {C H}_{2}

{C H}_{3} - C H = C H - {C H}_{3}

{C H}_{3} - C_{3} = C H - {C H}_{3}

{C H}_{3} - {C H}_{3} | C = {C H}_{3} | C - {C H}_{3}

(A) C H_{3} - C H_{2} - C | B r H - + C H - C H_{3}

(B) C H_{3} - C H_{2} - C | I H - + C H - C H_{3}

I . ⊖ C H_{2} - \oplus C H - C H = C H - O - C H_{3}

I I . ⊖ C H_{2} - C H = C H - \oplus C H - O - C H_{3}

I I I . C H_{2} = C H - ⊖ C H - \oplus C H - O - C H_{3}

I V . C H_{2} = C H - ⊖ C H - C H = \oplus O - C H_{3}

C H_{2} = C H - C H = C H - O - C H_{3}

C H_{3} - C | H C H_{3} - P h | C H - N H_{2}

π

C H_{3} - C H = C H_{2} (I)

C H_{3} - C | C H_{3} = C | C H_{3} - C H_{3} (I I)

C H_{3} - C | C H_{3} = C H_{2} (I I I)

C H_{3} - C | C H_{3} = C H - C H_{3} (I V)

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