Question

Change the given exponential expressions into logarithmic expressions $3^x=m$ and $x^2=a$.

• A. $x={\log }_{3}m$ and $2={\log }_{x}a$
• B. $3={\log }_{x}m$ and $2={\log }_{x}a$
• C. $x={\log }_{3}m$ and $x={\log }_{2}a$
• D. None of the above

Answer 1

The correct option is A $x={\log }_{3}m$ and $2={\log }_{x}a$

We know, $y=a^x$ can be written as $x={\log }_{a}y$.

$3^x=mx={\log }_{3}m$

$x^2=a2={\log }_{x}a$