Change the given exponential expressions into logarithmic expressions $3^{x} = m$ and $x^{2} = a$ .

x = {log}_{3} m

and

2 = {log}_{x} a

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3 = {log}_{x} m

and

2 = {log}_{x} a

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x = {log}_{3} m

and

x = {log}_{2} a

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None of the above

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Solution

The correct option is A $x = {log}_{3} m$ and $2 = {log}_{x} a$
We know, $y = a^{x}$ can be written as $x = {log}_{a} y$ .

$3^{x} = m x = {log}_{3} m$

$x^{2} = a 2 = {log}_{x} a$

Suggest Corrections

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