Charge to mass ratio of electron
Electrons are thermally emitted from a surface and accelerated through a potential difference V. The kinetic energy of the accelerated electrons equals the energy they gain as a result of being accelerated through the potential difference. In other words:
½ m v2 = eV
and solving for velocity,
v = (2eV/m)1/2 .
In this equation m is the mass of the electron and e is the charge of the electron.
The beam of electrons enters the region where a magnetic field B is set up by the Helmholz coils. The beam is deflected into a circular path of radius R by the magnetic force and undergoes a centripetal acceleration. This can be expressed as
evB = mv2/r
When the velocity is eliminated between the above two equations, then the charge to mass ratio can be written as
e/m = 2V/(B2r2)
The magnetic field due to the Helmholz coils can be expressed asB = 8moNI/(125)1/2a
where N is the number of turns of wire on each coil, I is the current through the coils, a is the mean radius of the coils, and mo is the permeability of free space. (mo = 4p x 10-7 Tm/A)
While carrying out discharge tube experiment, Thomson observed that the particles of the cathode deviate from their path. He noticed the amount of deviation in the presence of electrical or magnetic field depends on various related parameters. They are:
experimental observations.
The charge to mass ratio of the electron is given by :
e/m = 1.76 × 1011 C/kg
Where,
m = mass of an electron in kg = 9.10938356 × 10-31 kilograms.
e = magnitude of the charge of an electron in coulombs = 1.602 x 10-19 coulombs.