Electric Potential at a Point in Space Due to a Point Charge Q
Charges +50...
Question
Charges +50,+20,+30 and −100 nano coulomb are placed at the four corners of a square of side 5√2 cm. The potential at the intersection of diagonals is :
A
1.8√2×104V
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B
3.6×104V
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C
1.8×104V
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D
Zero
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Solution
The correct option is DZero Potential at centre is sum of potential due to individual charges V=k(50)5+k(20)5+k(−100)5+k(30)5