Question

Charges of $\frac{10}{3}mC$ are placed at the four vertices of a square of side $8cm$. The electric potential at the centre is :

• A. $150\sqrt{2}MV$
• B. $900\sqrt{2}MV$
• C. $1500\sqrt{2}MV$
• D. $9000\sqrt{2}MV$

Answer 1

The correct option is C $1500\sqrt{2}MV$

We know that the electric potential $V=\frac{q}{4\pi {ϵ}_{0}r}$

Here $q=\frac{10\times {10}^{-3}}{3}C$, $r=\frac{8\times {10}^{-2}}{\sqrt{2}}m$, $\frac{1}{4\pi {ϵ}_0}=9\times {10}^{9}SIunits$

Since there are four charges, the potential due to one charge will get multiplied by 4.

So, $V=1500\sqrt{2}MV$