Electric Potential at a Point in Space Due to a Point Charge Q
Charges of +1...
Question
Charges of +103×10−9Care placed at each of the four corners of a square of side 8 cm. The potential at the intersection of the diagonals is
A
150√2 volt
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B
1500√2 volt
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C
900√2 volt
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D
900 volt
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Solution
The correct option is B1500√2 volt Potential at the centre O, V=4×14πϵ0.Qa√2
where Q=103×10−9C and a=8cm=8×10−2m
So V=4×9×109×103×10−98×10−2√2=1500√2 volt