A line parallel to the x-axis is of the form of y=k where, k is constant.
Given equation: 4y−3x=3y−3x+1
4y−3x=3y−3x+1
4y−3y=−3x+3x+1
y=1
Since, the line 4y−3x=3y−3x+1 is of the form of y=k i.e y=1.
Therefore, the line 4y−3x=3y−3x+1 is parallel to x-axis.