Check whether the point $(b, a)$ lies on the straight line $a x + b y - a b = 0$ .

Open in App

Solution

If point (b, a) lies on the line ax +by –ab = 0, then it must satisfy the equation
$\Rightarrow$ ax + by = ab (divide both side by ab)
$\Rightarrow$ $\frac{x}{b}$ + $\frac{y}{a}$ = 1
Putting the value of points in the given equation
$\Rightarrow$ $\frac{b}{b}$ + $\frac{a}{a}$ = 1
$\Rightarrow$ 1 + 1 $\neq$ 1
Since, LHS $\neq$ RHS. Given point does not lie on the line.

Suggest Corrections

Similar questions

The point (b, a) lies on the straight line ax + by – ab = 0. State whether true or false.

The point $(b, a)$ lies on the straight line $a x + b y - a b = 0$ .

Point (b, a) lies on the straight line ax + by –ab = 0. State with true or false.

Q. Check whether the point

(1, 7)

lies on the line

5 x - 9 y + 2 = 0

or not?

If point $P (a, b)$ lies on the straight line $3 x + 2 y - 16 = 0$ and the point $Q (b, a)$ lies on the straight line $4 x - y - 5 = 0$ . The equation of the line $P Q$ is

Join BYJU'S Learning Program

Check whether the point (b,a) lies on the straight line ax+by–ab=0.

If point (b, a) lies on the line ax +by –ab = 0, then it must satisfy the equation ⇒ ax + by = ab (divide both side by ab) ⇒ xb + ya = 1 Putting the value of points in the given equation ⇒ bb+ aa = 1 ⇒ 1 + 1 ≠ 1 Since, LHS ≠ RHS. Given point does not lie on the line.

Check whether the point $(b, a)$ lies on the straight line $a x + b y - a b = 0$ .