Question

The point $(b,a)$ lies on the straight line $ax+by–ab=0$.

• A. True
• B. False

Answer 1

The correct option is B

False

If point $(b,a)$ lies on the line $ax+by–ab=0$, then it must satisfy the equation.

$\Rightarrow$ $ax+by=ab$ (dividing both sides by $ab$)

$\Rightarrow$ $\frac{x}{b}+\frac{y}{a}=1$

Putting the value of points in the given equation,

$\Rightarrow$ $\frac{b}{b}+\frac{a}{a}=1$

$\Rightarrow$ $1+1\ne 1$

Since, LHS $\ne$ RHS. Given point does not lie on the line.