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Action of Water on Calcium Carbide

Chemical equa...

Question

Chemical equations of preparing some substance are given. Which of the given chemical equation is used for the preparation of ethyne?
(1) $C H_{3} C O O N a + C a O + N a O H Δ \to C H_{4} + N a_{2} C O_{3}$
(2) $C a C_{2} + 2 H_{2} O \to H C \equiv C H + C a (O H)_{2}$
(3) $C H_{3} C H_{2} O H 443 K ⟶ H_{2} S O_{4} C H_{2} = C H_{2} + H_{2} O$

(1)

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(2)

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(3)

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(1)

and

(2)

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Solution

The correct option is B $(2)$
$C a C_{2} + 2 H_{2} O \to H C \equiv C H + C a (O H)_{2}$

Ethyne can be prepared by reacting calcium carbide with water.

Option B is correct.

Suggest Corrections

Similar questions

C H_{2} = C H_{2} H C l \to C H_{3} - C H_{2} . C l

n C H_{2} = C H_{2} \to (C H_{2} - C H_{3})_{n}

C H_{3} - C O O H + C H_{3} - C H_{2} - O H \to C H_{3} - C O O C H_{2} C H_{3} + H_{2} O

C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

H C \equiv C H + H_{2} P d - B a S O_{4} \to C H_{2} = C H_{2}

n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}

C H_{3} - C H_{2} - C O O - C H_{3}

C H_{3} - C H_{2} - C O O H

C H_{3} - C H_{2} - C O - C H_{3}

C H_{3} - O H

C H_{3} - C H_{2} - C H_{2} O H

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20

C a C_{2} + 2 H_{2} O \to C a (O H)_{2} + C_{2} H_{2}

H C \equiv C H + H_{2} P d \cdot B a S O_{4} - ----- \to C H_{2} = C H_{2}

n C H_{2} = C H_{2} \to (- C H_{2} - C H_{2} -)_{n} P o l y t h e n e

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